JEE Main 2022 · 28 Jul · Shift 2 · Chemistry Q34

ChemistrySingle correct+4 / -1Question 34 of 90

The products obtained during treatment of hard water using Clark's method are :

\mathrm{CaCO_3}

and

\mathrm{MgCO_3}

\mathrm{Ca(OH)_2}

and

\mathrm{Mg(OH)_2}

\mathrm{CaCO_3}

and

\mathrm{Mg(OH)_2}

\mathrm{Ca(OH)_2}

and

\mathrm{MgCO_3}

Answer and worked solution

Official answer: C

Clark's method. Lime precipitates $\mathrm{CaCO_3}$ and $\mathrm{Mg(OH)_2}$ .

(C)

Topics:Water and hydrogen peroxide

JEE Main 2022 · 28 Jul · Shift 2, Chemistry question 34