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JEE Main 2022 · 28 Jul · Shift 1, Physics question 54

The frequencies at which the current amplitude in an LCR series circuit becomes 12\dfrac1{\sqrt2} times its maximum value, are 212 rad s−1^{-1} and 232 rad s−1^{-1}. The value of resistance in the circuit is R = 5 Ω. The self inductance in the circuit is ______ mH.

Answer and worked solution

Official answer: 250

Bandwidth Δω=RL=20\Delta\omega=\frac RL=20 rad s−1^{-1}, so L=0.25L=0.25 H.

Answer: 250

Topics:LCR circuits and resonance
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