Skip to content
dronacharya.ai
← JEE Main 2022 · 28 Jul · Shift 1
MathematicsInteger+4 / -1Question 30 of 90

JEE Main 2022 · 28 Jul · Shift 1, Mathematics question 30

The sum of all real values of xx for which 3x2−9x+17x2+3x+10=5x2−7x+193x2+5x+12\dfrac{3x^2-9x+17}{x^2+3x+10}=\dfrac{5x^2-7x+19}{3x^2+5x+12} is equal to ______.

Answer and worked solution

Official answer: 6

Cross-multiply. 4x4−20x3−6x2−10x+14=04x^4-20x^3-6x^2-10x+14=0, which factors as 2(x2+x+1)(2x2−12x+7)2(x^2+x+1)(2x^2-12x+7).

Real roots come from 2x2−12x+7=02x^2-12x+7=0, with sum 6.

Answer: 6