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← JEE Main 2022 · 28 Jul · Shift 1
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JEE Main 2022 · 28 Jul · Shift 1, Mathematics question 22

Let P(−2,−1,1)P(-2,-1,1) and Q(5617,4317,11117)Q\left(\dfrac{56}{17},\dfrac{43}{17},\dfrac{111}{17}\right) be the vertices of the rhombus PRQS. If the direction ratios of the diagonal RS are α,−1,β\alpha,-1,\beta, where both α\alpha and β\beta are integers of minimum absolute values, then α2+β2\alpha^2+\beta^2 is equal to ______.

Answer and worked solution

Official answer: 450

PQ direction ∝(45,30,47)\propto(45,30,47). The diagonals of a rhombus are perpendicular, so 45α−30+47β=045\alpha-30+47\beta=0.

Smallest integers. α=−15\alpha=-15, β=15\beta=15.

Answer: 450