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← JEE Main 2022 · 28 Jul · Shift 1
MathematicsSingle correct+4 / -1Question 18 of 90

JEE Main 2022 · 28 Jul · Shift 1, Mathematics question 18

Let α\alpha, β\beta and γ\gamma be three positive real numbers. Let f(x)=αx5+βx3+γxf(x)=\alpha x^5+\beta x^3+\gamma x, x∈Rx\in\mathbf R and g:R→Rg:\mathbf R\to\mathbf R be such that g(f(x))=xg(f(x))=x for all x∈Rx\in\mathbf R. If a1,a2,a3,…,ana_1,a_2,a_3,\ldots,a_n be in arithmetic progression with mean zero, then the value of f(g(1n∑i=1nf(ai)))f\left(g\left(\dfrac1n\displaystyle\sum_{i=1}^nf(a_i)\right)\right) is equal to :

Choose one option
Answer and worked solution

Official answer: A

f is odd and increasing, so g is its inverse. A symmetric AP with mean 0 gives ∑f(ai)=0\sum f(a_i)=0.

f(g(0))=0f(g(0))=0. (A)