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← JEE Main 2022 · 28 Jul · Shift 1
ChemistryInteger+4 / -1Question 88 of 90

JEE Main 2022 · 28 Jul · Shift 1, Chemistry question 88

The disproportionation of MnO42−\mathrm{MnO_4^{2-}} in acidic medium resulted in the formation of two manganese compounds A and B. If the oxidation state of Mn in B is smaller than that of A, then the spin-only magnetic moment (μ) value of B in BM is ______. (Nearest integer)

Answer and worked solution

Official answer: 4

Disproportionation. 3MnO42−+4H+→2MnO4−+MnO2+2H2O\mathrm{3MnO_4^{2-}+4H^+\rightarrow2MnO_4^-+MnO_2+2H_2O}.

B is MnO2\mathrm{MnO_2} (Mn⁴⁺, d3d^3): 15=3.87≈4\sqrt{15}=3.87\approx4 BM.

Answer: 4