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← JEE Main 2022 · 27 Jul · Shift 2
PhysicsInteger+4 / -1Question 55 of 90

JEE Main 2022 · 27 Jul · Shift 2, Physics question 55

As show in the figure, in steady state, the charge stored in the capacitor is ______ ×10−6\times10^{-6} C.

Cell E = 10 V with internal r = 10 Ω, across R = 100 Ω; in parallel with R a branch of C = 1.1 μF in series with R′ = 200 Ω.
Answer and worked solution

Official answer: 10

Steady state. No current flows in the capacitor branch. I=10110I=\frac{10}{110} A, so the voltage across R is 10011\frac{100}{11} V.

Charge 1.1×10011=101.1\times\frac{100}{11}=10 μC.

Answer: 10