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← JEE Main 2022 · 27 Jul · Shift 2
PhysicsInteger+4 / -1Question 53 of 90

JEE Main 2022 · 27 Jul · Shift 2, Physics question 53

A thin prism of angle 6° and refractive index for yellow light (nY)(n_Y) 1.5 is combined with another prism of angle 5° and nY=1.55n_Y=1.55. The combination produces no dispersion. The net average deviation (δ) produced by the combination is (1x)∘\left(\dfrac1x\right)^\circ. The value of xx is ______.

Two thin prisms P1 (angle A1 = 6°) and P2 (angle A2 = 5°) placed inverted against each other; a ray passes through both and leaves deviated by δ.
Answer and worked solution

Official answer: 4

Net deviation with the prisms opposed: (1.5−1)6−(1.55−1)5=3−2.75=0.25∘=(14)∘(1.5-1)6-(1.55-1)5=3-2.75=0.25^\circ=\left(\frac14\right)^\circ.

Answer: 4