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← JEE Main 2022 · 27 Jul · Shift 2
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JEE Main 2022 · 27 Jul · Shift 2, Physics question 49

For a constant collector-emitter voltage of 8 V, the collector current of a transistor reached to the value of 6 mA from 4 mA, whereas base current changed from 20 μA to 25 μA value. If transistor is in active state, small signal current gain (current amplification factor) will be :

Choose one option
Answer and worked solution

Official answer: B

Gain. β=ΔICΔIB=2 mA5 μA=400\beta=\frac{\Delta I_C}{\Delta I_B}=\frac{2\text{ mA}}{5\ \mu\text A}=400.

(B)

Topics:Transistors
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