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← JEE Main 2022 · 27 Jul · Shift 2
PhysicsSingle correct+4 / -1Question 35 of 90

JEE Main 2022 · 27 Jul · Shift 2, Physics question 35

The velocity of the bullet becomes one third after it penetrates 4 cm in a wooden block. Assuming that bullet is facing a constant resistance during its motion in the block. The bullet stops completely after travelling at (4+x)(4+x) cm inside the block. The value of xx is :

Choose one option
Answer and worked solution

Official answer: C

Deceleration. u29=u2−2a(4)\frac{u^2}9=u^2-2a(4) gives a=u29a=\frac{u^2}9.

Stopping distance u22a=4.5\frac{u^2}{2a}=4.5 cm, so x=0.5x=0.5.

(C)