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← JEE Main 2022 · 27 Jul · Shift 2
MathematicsInteger+4 / -1Question 25 of 90

JEE Main 2022 · 27 Jul · Shift 2, Mathematics question 25

A water tank has the shape of a right circular cone with axis vertical and vertex downwards. Its semi-vertical angle is tan⁡−134\tan^{-1}\dfrac34. Water is poured in it at a constant rate of 6 cubic meter per hour. The rate (in square meter per hour), at which the wet curved surface area of the tank is increasing, when the depth of water in the tank is 4 meters, is ______.

Answer and worked solution

Official answer: 5

Cone. r=34hr=\frac34h, so V=3πh316V=\frac{3\pi h^3}{16} and the curved area is S=πr⋅54h=15πh216S=\pi r\cdot\frac54h=\frac{15\pi h^2}{16}.

Rates at h = 4. 9πdhdt=69\pi\frac{dh}{dt}=6, and dSdt=15π2⋅23π=5\frac{dS}{dt}=\frac{15\pi}2\cdot\frac2{3\pi}=5.

Answer: 5