JEE Main 2022 · 27 Jul · Shift 2 · Mathematics Q8

MathematicsSingle correct+4 / -1Question 8 of 90

The area of the region enclosed by $y\le4x^2$ , $x^2\le9y$ and $y\le4$ , is equal to :

\dfrac{40}3

\dfrac{56}3

\dfrac{112}3

\dfrac{80}3

Answer and worked solution

Official answer: D

Region for $0\le y\le4$ : $\frac{\sqrt y}2\le|x|\le3\sqrt y$ .

Area $2\int_0^4\frac52\sqrt y\,dy=5\cdot\frac23\cdot8=\frac{80}3$ .

(D)

Topics:Area between curves

JEE Main 2022 · 27 Jul · Shift 2, Mathematics question 8