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← JEE Main 2022 · 27 Jul · Shift 2
ChemistryInteger+4 / -1Question 85 of 90

JEE Main 2022 · 27 Jul · Shift 2, Chemistry question 85

[A]Reactant→[B]Product\underset{\text{Reactant}}{[A]}\rightarrow\underset{\text{Product}}{[B]}

If formation of compound [B] follows the first order of kinetics and after 70 minutes the concentration of [A] was found to be half of its initial concentration. Then the rate constant of the reaction is x×10−6x\times10^{-6} s−1^{-1}. The value of xx is ______. (Nearest Integer)

Answer and worked solution

Official answer: 165

First order. k=0.69370×60=1.65×10−4k=\frac{0.693}{70\times60}=1.65\times10^{-4} s−1^{-1}.

Answer: 165