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← JEE Main 2022 · 27 Jul · Shift 2
ChemistryInteger+4 / -1Question 83 of 90

JEE Main 2022 · 27 Jul · Shift 2, Chemistry question 83

A gas (Molar mass = 280 g mol−1^{-1}) was burnt in excess O2\mathrm{O_2} in a constant volume calorimeter and during combustion the temperature of calorimeter increased from 298.0 K to 298.45 K. If the heat capacity of calorimeter is 2.5 kJ K−1^{-1} and enthalpy of combustion of gas is 9 kJ mol−1^{-1} then amount of gas burnt is ______ g. (Nearest Integer)

Answer and worked solution

Official answer: 35

Heat released 2.5×0.45=1.1252.5\times0.45=1.125 kJ, i.e. 1.1259=0.125\frac{1.125}9=0.125 mol.

Mass 0.125×280=350.125\times280=35 g.

Answer: 35