JEE Main 2022 · 27 Jul · Shift 2 · Chemistry Q81

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ChemistryInteger+4 / -1Question 81 of 90

The normality of $\mathrm{H_2SO_4}$ in the solution obtained on mixing 100 mL of 0.1 M $\mathrm{H_2SO_4}$ with 50 mL of 0.1 M NaOH is ______ $\times10^{-1}$ N. (Nearest Integer)

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Answer and worked solution

Official answer: 1

Equivalents. $\mathrm{H_2SO_4}$ gives $100\times0.1\times2=20$ meq; NaOH 5 meq. That leaves 15 meq in 150 mL: 0.1 N.

Answer: 1

Topics:Equivalent concept and normality

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JEE Main 2022 · 27 Jul · Shift 2, Chemistry question 81