Skip to content
dronacharya.ai
← JEE Main 2022 · 27 Jul · Shift 2
ChemistryList match+4 / -1Question 74 of 90

JEE Main 2022 · 27 Jul · Shift 2, Chemistry question 74

Match List - I with List - II.

Choose the correct answer from the options given below :

Four reactions giving aldehydes: benzoyl chloride with H2/Pd-BaSO4; CH3CN with SnCl2/HCl then H3O+; toluene with CrO2Cl2 then H3O+; benzene with CO, HCl, anhydrous AlCl3.

List - I

  • A
    Benzoyl chloride →H2, Pd-BaSO4\xrightarrow{\mathrm{H_2,\ Pd\text-BaSO_4}} benzaldehyde
  • B
    CH3CN→SnCl2/HCl, H3O+CH3CHO\mathrm{CH_3CN\xrightarrow{SnCl_2/HCl,\ H_3O^+}CH_3CHO}
  • C
    Toluene →CrO2Cl2, H3O+\xrightarrow{\mathrm{CrO_2Cl_2,\ H_3O^+}} benzaldehyde
  • D
    Benzene →CO, HCl, AlCl3 (anhyd)\xrightarrow{\mathrm{CO,\ HCl,\ AlCl_3\ (anhyd)}} benzaldehyde

List - II

  • I
    Gatterman Koch reaction
  • II
    Etard reaction
  • III
    Stephen reaction
  • IV
    Rosenmund reaction
Choose one option
Answer and worked solution

Official answer: A

Reactions. Rosenmund (acid chloride), Stephen (nitrile), Etard (toluene with CrO2Cl2\mathrm{CrO_2Cl_2}), Gatterman-Koch (benzene with CO, HCl).

A-IV, B-III, C-II, D-I. (A)