JEE Main 2022 · 27 Jul · Shift 2 · Chemistry Q61

ChemistrySingle correct+4 / -1Question 61 of 90

The correct decreasing order of energy for the orbitals having, following set of quantum numbers :

(A) n = 3, l = 0, m = 0
(B) n = 4, l = 0, m = 0
(C) n = 3, l = 1, m = 0
(D) n = 3, l = 2, m = 1

is :

(D) > (B) > (C) > (A)

(B) > (D) > (C) > (A)

(B) > (C) > (D) > (A)

Answer and worked solution

Official answer: A

Orbitals. (A) 3s, (B) 4s, (C) 3p, (D) 3d.

Order by $n+l$ , then n: $3d>4s>3p>3s$ .

(A)

Topics:Quantum numbers Electronic configuration

JEE Main 2022 · 27 Jul · Shift 2, Chemistry question 61