JEE Main 2022 · 27 Jul · Shift 1 · Physics Q46

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PhysicsSingle correct+4 / -1Question 46 of 90

A microscope was initially placed in air (refractive index 1). It is then immersed in oil (refractive index 2). For a light whose wavelength in air is $\lambda$ , calculate the change of microscope's resolving power due to oil and choose the correct option.

Resolving power will be

\dfrac14

in the oil than it was in the air.

Resolving power will be twice in the oil than it was in the air.

Resolving power will be four times in the oil than it was in the air.

Resolving power will be

\dfrac12

in the oil than it was in the air.

Answer and worked solution

Official answer: B

Resolving power $\propto n\sin\theta$ (numerical aperture), so oil with $n=2$ doubles it.

(B)

Topics:Resolving power

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JEE Main 2022 · 27 Jul · Shift 1, Physics question 46