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← JEE Main 2022 · 27 Jul · Shift 1
MathematicsSingle correct+4 / -1Question 12 of 90

JEE Main 2022 · 27 Jul · Shift 1, Mathematics question 12

Let a⃗=αi^+j^+βk^\vec a=\alpha\hat i+\hat j+\beta\hat k and b⃗=3i^−5j^+4k^\vec b=3\hat i-5\hat j+4\hat k be two vectors, such that a⃗×b⃗=−i^+9j^+12k^\vec a\times\vec b=-\hat i+9\hat j+12\hat k. Then the projection of b⃗−2a⃗\vec b-2\vec a on b⃗+a⃗\vec b+\vec a is equal to

Choose one option
Answer and worked solution

Official answer: Dropped: full marks to everyone

This question was dropped in NTA's final key.

As printed. a⃗×b⃗=(4+5β, 3β−4α, −5α−3)=(−1,9,12)\vec a\times\vec b=(4+5\beta,\,3\beta-4\alpha,\,-5\alpha-3)=(-1,9,12) gives β=−1\beta=-1, α=−3\alpha=-3. Then b⃗−2a⃗=(9,−7,6)\vec b-2\vec a=(9,-7,6) and b⃗+a⃗=(0,−4,3)\vec b+\vec a=(0,-4,3), so the projection is 465\frac{46}5, which is option (D).