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← JEE Main 2022 · 27 Jul · Shift 1
MathematicsSingle correct+4 / -1Question 5 of 90

JEE Main 2022 · 27 Jul · Shift 1, Mathematics question 5

The remainder when (2021)2022+(2022)2021(2021)^{2022}+(2022)^{2021} is divided by 7 is

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Answer and worked solution

Official answer: A

Mod 7. 2021≡52021\equiv5, 2022≡−12022\equiv-1. Since 56≡15^6\equiv1 and 6∣20226\mid2022, 52022≡15^{2022}\equiv1; (−1)2021=−1(-1)^{2021}=-1.

Remainder 1−1=01-1=0. (A)