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← JEE Main 2022 · 26 Jul · Shift 2
PhysicsInteger+4 / -1Question 52 of 90

JEE Main 2022 · 26 Jul · Shift 2, Physics question 52

The radius of gyration of a cylindrical rod about an axis of rotation perpendicular to its length and passing through the center will be ______ m.

Given, the length of the rod is 10310\sqrt3 m.

Answer and worked solution

Official answer: 5

Thin rod about its centre: K=L12=10323=5K=\frac L{\sqrt{12}}=\frac{10\sqrt3}{2\sqrt3}=5 m.

Answer: 5