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← JEE Main 2022 · 26 Jul · Shift 2
PhysicsSingle correct+4 / -1Question 48 of 90

JEE Main 2022 · 26 Jul · Shift 2, Physics question 48

Two masses M1M_1 and M2M_2 are tied together at the two ends of a light inextensible string that passes over a frictionless pulley. When the mass M2M_2 is twice that of M1M_1, the acceleration of the system is a1a_1. When the mass M2M_2 is thrice that of M1M_1, the acceleration of the system is a2a_2. The ratio a1a2\dfrac{a_1}{a_2} will be :

Atwood machine: M1 on the left and M2 on the right hanging from a string over a fixed pulley.
Choose one option
Answer and worked solution

Official answer: B

Atwood. a=(M2−M1)gM1+M2a=\frac{(M_2-M_1)g}{M_1+M_2}: a1=g3a_1=\frac g3, a2=g2a_2=\frac g2, ratio 23\frac23.

(B)