JEE Main 2022 · 26 Jul · Shift 2 · Chemistry Q86

← JEE Main 2022 · 26 Jul · Shift 2

ChemistryInteger+4 / -1Question 86 of 90

The number of non-ionisable protons present in the product B obtained from the following reactions is ______.

$\mathrm{C_2H_5OH+PCl_3\rightarrow C_2H_5Cl+A}$

$\mathrm{A+PCl_3\rightarrow B}$

Your answer

Answer and worked solution

Official answer: 2

A is $\mathrm{H_3PO_3}$ ( $\mathrm{3C_2H_5OH+PCl_3\rightarrow3C_2H_5Cl+H_3PO_3}$ ).

B. $\mathrm{H_3PO_3}$ with $\mathrm{PCl_3}$ gives pyrophosphorous acid $\mathrm{H_4P_2O_5}$ ( $\mathrm{5H_3PO_3+PCl_3\rightarrow3H_4P_2O_5+3HCl}$ ), which has two P-H bonds. Those H atoms are not ionisable.

Answer: 2

Topics:Oxoacids Alcohols

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JEE Main 2022 · 26 Jul · Shift 2, Chemistry question 86