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← JEE Main 2022 · 26 Jul · Shift 2
ChemistryInteger+4 / -1Question 81 of 90

JEE Main 2022 · 26 Jul · Shift 2, Chemistry question 81

A 10 g mixture of hydrogen and helium is contained in a vessel of capacity 0.0125 m3^3 at 6 bar and 27°C. The mass of helium in the mixture is ______ g. (nearest integer)

Given: R = 8.3 J K−1^{-1} mol−1^{-1} (Atomic masses of H and He are 1 u and 4 u, respectively)

Answer and worked solution

Official answer: 8

Moles. n=PVRT=6×105×0.01258.3×300=3.01n=\frac{PV}{RT}=\frac{6\times10^5\times0.0125}{8.3\times300}=3.01.

Split. x+y=3.01x+y=3.01 and 2x+4y=102x+4y=10 (H₂ and He): y=1.99y=1.99 mol He, i.e. 7.95 g.

Answer: 8