Skip to content
dronacharya.ai
← JEE Main 2022 · 26 Jul · Shift 1
PhysicsInteger+4 / -1Question 53 of 90

JEE Main 2022 · 26 Jul · Shift 1, Physics question 53

In an experiment to determine the Young's modulus of wire of a length exactly 1 m, the extension in the length of the wire is measured as 0.4 mm with an uncertainty of ± 0.02 mm when a load of 1 kg is applied. The diameter of the wire is measured as 0.4 mm with an uncertainty of ± 0.01 mm. The error in the measurement of Young's modulus (ΔY\Delta Y) is found to be x×1010x\times10^{10} Nm−2^{-2}. The value of xx is ______.

(take g=10g=10 ms−2^{-2})

Answer and worked solution

Official answer: 2

Young's modulus Y=4FLπd2Δl≈2×1011Y=\frac{4FL}{\pi d^2\Delta l}\approx2\times10^{11} N m−2^{-2}; relative error 0.05+0.05=0.10.05+0.05=0.1.

ΔY =2×1010=2\times10^{10}.

Answer: 2