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← JEE Main 2022 · 26 Jul · Shift 1
PhysicsSingle correct+4 / -1Question 45 of 90

JEE Main 2022 · 26 Jul · Shift 1, Physics question 45

A water drop of radius 1 cm is broken into 729 equal droplets. If surface tension of water is 75 dyne/cm, then the gain in surface energy upto first decimal place will be :

(Given π=3.14\pi=3.14)

Choose one option
Answer and worked solution

Official answer: C

Droplet radius 19\frac19 cm; extra area 4π(729r2−R2)=4π×84\pi(729r^2-R^2)=4\pi\times8 cm².

Energy 75×32π×10−7≈7.5×10−475\times32\pi\times10^{-7}\approx7.5\times10^{-4} J.

(C)