JEE Main 2022 · 26 Jul · Shift 1 · Physics Q40 · Dronacharya Exams

My attemptsTake a paper

← JEE Main 2022 · 26 Jul · Shift 1

PhysicsSingle correct+4 / -1Question 40 of 90

The current I in the given circuit will be :

A 40 V source drives current I through a network of five resistors: two 4 Ω and a 2 Ω across the top, and further 4 Ω resistors forming parallel paths to the return line.

A

10 A

B

20 A

C

4 A

D

40 A

Answer and worked solution

Official answer: A

Equivalent resistance. The two left 4 Ω resistors share both end nodes (2 Ω); the remaining 2 Ω, 4 Ω and 4 Ω reduce with them to a total of 4 Ω.

Current $\frac{40}4=10$ A.

(A)

Topics:Series and parallel resistors

← Previous question Next question →