JEE Main 2022 · 26 Jul · Shift 1 · Physics Q36

PhysicsSingle correct+4 / -1Question 36 of 90

The magnetic field of a plane electromagnetic wave is given by :

$\vec B=2\times10^{-8}\sin\left(0.5\times10^3x+1.5\times10^{11}t\right)\hat j\ \text{T}.$

The amplitude of the electric field would be :

6 Vm

^{-1}

along

x

-axis

3 Vm

^{-1}

along

z

-axis

6 Vm

^{-1}

along

z

-axis

2\times10^{-8}

^{-1}

along

z

-axis

Answer and worked solution

Official answer: C

$E_0=cB_0$ $=6$ V m $^{-1}$ . The wave moves along $-x$ with B along y, so E is along z.

(C)

Topics:Properties of EM waves

JEE Main 2022 · 26 Jul · Shift 1, Physics question 36