JEE Main 2022 · 26 Jul · Shift 1 · Physics Q33

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PhysicsSingle correct+4 / -1Question 33 of 90

The disintegration rate of a certain radioactive sample at any instant is 4250 disintegrations per minute. 10 minutes later, the rate becomes 2250 disintegrations per minute. The approximate decay constant is :

(Take $\log_{10}1.88=0.274$ )

0.02 min

^{-1}

2.7 min

^{-1}

0.063 min

^{-1}

6.3 min

^{-1}

Answer and worked solution

Official answer: C

Decay constant $\lambda=\frac{2.303}{10}\log\frac{4250}{2250}=\frac{2.303\times0.274}{10}\approx0.063$ min $^{-1}$ .

(C)

Topics:Radioactive decay

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JEE Main 2022 · 26 Jul · Shift 1, Physics question 33