JEE Main 2022 · 26 Jul · Shift 1, Mathematics question 8

If $f(x)=\begin{cases}x+a, & x\le0\\|x-4|, & x>0\end{cases}$ and $g(x)=\begin{cases}x+1, & x<0\\(x-4)^2+b, & x\ge0\end{cases}$ are continuous on $\mathbf R$, then $(g\circ f)(2)+(f\circ g)(-2)$ is equal to :