JEE Main 2022 · 26 Jul · Shift 1, Chemistry question 86

At 298 K, the equilibrium constant is $2\times10^{15}$ for the reaction :

$$\mathrm{Cu(s)+2Ag^+(aq)\rightleftharpoons Cu^{2+}(aq)+2Ag(s)}$$

The equilibrium constant for the reaction

$$\mathrm{\tfrac12Cu^{2+}(aq)+Ag(s)\rightleftharpoons\tfrac12Cu(s)+Ag^+(aq)}$$

is $x\times10^{-8}$. The value of $x$ is ______. (Nearest Integer)