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← JEE Main 2022 · 25 Jul · Shift 2
PhysicsInteger+4 / -1Question 60 of 90

JEE Main 2022 · 25 Jul · Shift 2, Physics question 60

Magnetic flux (in weber) in a closed circuit of resistance 20 Ω\Omega varies with time t(s) as ϕ=8t2−9t+5\phi=8t^2-9t+5. The magnitude of the induced current at t=0.25t=0.25 s will be ______ mA.

Answer and worked solution

Official answer: 250

emf ∣dϕdt∣=∣16t−9∣=5\left|\frac{d\phi}{dt}\right|=|16t-9|=5 V at 0.25 s: I=520=250I=\frac5{20}=250 mA.

Answer: 250