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JEE Main 2022 · 25 Jul · Shift 2, Physics question 53

A block of ice of mass 120 g at temperature 0°C is put in 300 g of water at 25°C. The xxg of ice melts as the temperature of the water reaches 0°C. The value of xx is ______.

[Use specific heat capacity of water = 4200 Jkg−1^{-1}K−1^{-1}, Latent heat of ice = 3.5×1053.5\times10^5 Jkg−1^{-1}]

Answer and worked solution

Official answer: 90

Heat from water 0.3×4200×25=315000.3\times4200\times25=31500 J melts 315003.5×105=0.09\frac{31500}{3.5\times10^5}=0.09 kg =90=90 g.

Answer: 90

Topics:Calorimetry and specific heatLatent heat and phase change
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