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JEE Main 2022 · 25 Jul · Shift 2, Physics question 51

A particle is moving in a straight line such that its velocity is increasing at 5 ms−1^{-1} per meter. The acceleration of the particle is ______ ms−2^{-2} at a point where its velocity is 20 ms−1^{-1}.

Answer and worked solution

Official answer: 100

a=vdvdxa=v\dfrac{dv}{dx} =20×5=100=20\times5=100 m s−2^{-2}.

Answer: 100

Topics:Motion in a straight line
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