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JEE Main 2022 · 25 Jul · Shift 2, Physics question 47

A bag of sand of mass 9.8 kg is suspended by a rope. A bullet of 200 g travelling with speed 10 ms−1^{-1} gets embedded in it, then loss of kinetic energy will be :

Choose one option
Answer and worked solution

Official answer: B

Common speed 0.2×1010=0.2\frac{0.2\times10}{10}=0.2 m s−1^{-1}. Loss 10−0.2=9.810-0.2=9.8 J.

(B)

Topics:Elastic and inelastic collisions
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