JEE Main 2022 · 25 Jul · Shift 2 · Physics Q45

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PhysicsSingle correct+4 / -1Question 45 of 90

Let $\eta_1$ is the efficiency of an engine at $T_1=447$ °C and $T_2=147$ °C while $\eta_2$ is the efficiency at $T_1=947$ °C and $T_2=47$ °C. The ratio $\dfrac{\eta_1}{\eta_2}$ will be :

0.41

0.56

0.73

0.70

Answer and worked solution

Official answer: B

Efficiencies. $1-\frac{420}{720}=0.417$ and $1-\frac{320}{1220}=0.738$ : ratio 0.56.

(B)

Topics:Carnot cycle

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JEE Main 2022 · 25 Jul · Shift 2, Physics question 45