JEE Main 2022 · 25 Jul · Shift 2 · Physics Q42 · Dronacharya Exams

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A current of 15 mA flows in the circuit as shown in figure. The value of potential difference between the points A and B will be :

From A, a 5 kΩ resistor, then 10 kΩ and 5 kΩ in parallel, then a 10 kΩ resistor to B; a current of 15 mA flows.

A

50 V

B

75 V

C

150 V

D

275 V

Answer and worked solution

Official answer: D

Resistance $5+\frac{10\times5}{15}+10=\frac{55}3$ kΩ. Voltage $15\text{ mA}\times\frac{55}3\text{ kΩ}=275$ V.

(D)

Topics:Series and parallel resistors

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