JEE Main 2022 · 25 Jul · Shift 2 · Physics Q39

← JEE Main 2022 · 25 Jul · Shift 2

PhysicsSingle correct+4 / -1Question 39 of 90

Light wave traveling in air along x-direction is given by $E_y=540\sin\pi\times10^4(x-ct)$ Vm $^{-1}$ . Then, the peak value of magnetic field of wave will be (Given $c=3\times10^8$ ms $^{-1}$ )

18\times10^{-7}

54\times10^{-7}

54\times10^{-8}

18\times10^{-8}

Answer and worked solution

Official answer: A

$B_0=\frac{E_0}c$ $=\frac{540}{3\times10^8}=18\times10^{-7}$ T.

(A)

Topics:Properties of EM waves

← Previous question Next question →

JEE Main 2022 · 25 Jul · Shift 2, Physics question 39