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← JEE Main 2022 · 25 Jul · Shift 2
MathematicsInteger+4 / -1Question 27 of 90

JEE Main 2022 · 25 Jul · Shift 2, Mathematics question 27

Let an=∫−1n(1+x2+x23+⋯+xn−1n)dxa_n=\displaystyle\int_{-1}^n\left(1+\frac x2+\frac{x^2}3+\dots+\frac{x^{n-1}}n\right)dx for every n∈Nn\in\mathbb N. Then the sum of all the elements of the set {n∈N:an∈(2,30)}\{n\in\mathbb N:a_n\in(2,30)\} is ______.

Answer and worked solution

Official answer: 5

Integral an=∑k=1nnk−(−1)kk2a_n=\sum_{k=1}^n\dfrac{n^k-(-1)^k}{k^2}: a1=2a_1=2, a2=3.75a_2=3.75, a3≈9.1a_3\approx9.1, a4≈31.9a_4\approx31.9.

In (2,30) n=2,3n=2,3: sum 5.

Answer: 5