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← JEE Main 2022 · 25 Jul · Shift 2
MathematicsInteger+4 / -1Question 22 of 90

JEE Main 2022 · 25 Jul · Shift 2, Mathematics question 22

Let f(x)f(x) be a quadratic polynomial with leading coefficient 1 such that f(0)=pf(0)=p, p≠0p\ne0, and f(1)=13f(1)=\dfrac13. If the equations f(x)=0f(x)=0 and f∘f∘f∘f(x)=0f\circ f\circ f\circ f(x)=0 have a common real root, then f(−3)f(-3) is equal to ______.

Answer and worked solution

Official answer: 25

Common root α. f(α)=0f(\alpha)=0 makes f4(α)=f(f(f(0)))=f(f(p))f^{4}(\alpha)=f(f(f(0)))=f(f(p)), so f(p)f(p) must be a root. With b=−23−pb=-\frac23-p: f(p)=p3f(p)=\frac p3.

Condition f(p3)=0f\left(\frac p3\right)=0: p+3b+9=0p+3b+9=0, so p=72p=\frac72, b=−256b=-\frac{25}6.

Value f(−3)=9+12.5+3.5=25f(-3)=9+12.5+3.5=25.

Answer: 25