JEE Main 2022 · 25 Jul · Shift 2 · Mathematics Q19

← JEE Main 2022 · 25 Jul · Shift 2

MathematicsSingle correct+4 / -1Question 19 of 90

$2\sin\left(\dfrac\pi{22}\right)\sin\left(\dfrac{3\pi}{22}\right)\sin\left(\dfrac{5\pi}{22}\right)\sin\left(\dfrac{7\pi}{22}\right)\sin\left(\dfrac{9\pi}{22}\right)$ is equal to :

\dfrac3{16}

\dfrac1{16}

\dfrac1{32}

\dfrac9{32}

Answer and worked solution

Official answer: B

Product. $\prod_{k=1}^5\sin\frac{(2k-1)\pi}{22}=\frac1{32}$ , so twice it is $\frac1{16}$ .

(B)

Topics:Trigonometric ratios and identities

← Previous question Next question →

JEE Main 2022 · 25 Jul · Shift 2, Mathematics question 19