JEE Main 2022 · 25 Jul · Shift 2 · Mathematics Q1

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For $z\in\mathbb C$ if the minimum value of $\left(\left|z-3\sqrt2\right|+\left|z-p\sqrt2i\right|\right)$ is $5\sqrt2$ , then a value of $p$ is ______.

\dfrac72

\dfrac92

Answer and worked solution

Official answer: C

Minimum of $|z-a|+|z-b|$ is $|a-b|=\sqrt{18+2p^2}=5\sqrt2$ , so $p^2=16$ and $p=4$ is a value.

(C)

Topics:Geometry in the complex plane

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JEE Main 2022 · 25 Jul · Shift 2, Mathematics question 1