Skip to content
dronacharya.ai
← JEE Main 2022 · 25 Jul · Shift 2
ChemistryInteger+4 / -1Question 84 of 90

JEE Main 2022 · 25 Jul · Shift 2, Chemistry question 84

While performing a thermodynamics experiment, a student made the following observations.

HCl+NaOH→NaCl+H2O\mathrm{HCl+NaOH\rightarrow NaCl+H_2O} ΔH=−57.3\Delta H=-57.3 kJ mol−1^{-1}

CH3COOH+NaOH→CH3COONa+H2O\mathrm{CH_3COOH+NaOH\rightarrow CH_3COONa+H_2O} ΔH=−55.3\Delta H=-55.3 kJ mol−1^{-1}

The enthalpy of ionization of CH3COOH\mathrm{CH_3COOH} as calculated by the student is ______ kJ mol−1^{-1}. (nearest integer)

Answer and worked solution

Official answer: 2

Ionisation enthalpy 57.3−55.3=257.3-55.3=2 kJ mol−1^{-1}.

Answer: 2