Skip to content
dronacharya.ai
← JEE Main 2022 · 25 Jul · Shift 2
ChemistryInteger+4 / -1Question 82 of 90

JEE Main 2022 · 25 Jul · Shift 2, Chemistry question 82

A sealed flask with a capacity of 2 dm3^3 contains 11 g of propane gas. The flask is so weak that it will burst if the pressure becomes 2 MPa. The minimum temperature at which the flask will burst is ______ °C. [Nearest integer]

(Given: R = 8.3 J K−1^{-1} mol−1^{-1}, Atomic masses of C and H are 12u and 1u, respectively.) (Assume that propane behaves as an ideal gas.)

Answer and worked solution

Official answer: 1655

Moles 1144=0.25\frac{11}{44}=0.25. T=PVnR=2×106×2×10−30.25×8.3≈1928T=\dfrac{PV}{nR}=\dfrac{2\times10^6\times2\times10^{-3}}{0.25\times8.3}\approx1928 K ≈1655\approx1655 °C.

Answer: 1655