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← JEE Main 2022 · 25 Jul · Shift 1
PhysicsInteger+4 / -1Question 56 of 90

JEE Main 2022 · 25 Jul · Shift 1, Physics question 56

The volume charge density of a sphere of radius 6 m is 2 μ\muC cm−3^{-3}. The number of lines of force per unit surface area coming out from the surface of the sphere is ______ ×1010\times10^{10} NC−1^{-1}.

[Given : Permittivity of vacuum ϵ0=8.85×10−12\epsilon_0=8.85\times10^{-12} C2^2 N−1^{-1} m−2^{-2}]

Answer and worked solution

Official answer: 45

Surface field. E=ρR3ε0=2×63×8.85×10−12≈4.5×1011=45×1010E=\dfrac{\rho R}{3\varepsilon_0}=\dfrac{2\times6}{3\times8.85\times10^{-12}}\approx4.5\times10^{11}=45\times10^{10} N C−1^{-1}.

Answer: 45

Topics:Electric flux and Gauss's law
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