JEE Main 2022 · 25 Jul · Shift 1 · Physics Q48

PhysicsSingle correct+4 / -1Question 48 of 90

The momentum of an electron revolving in n $^{\text{th}}$ orbit is given by : (Symbols have their usual meanings)

\dfrac{nh}{2\pi r}

\dfrac{nh}{2r}

\dfrac{nh}{2\pi}

\dfrac{2\pi r}{nh}

Answer and worked solution

Official answer: A

Bohr. $mvr=\frac{nh}{2\pi}$ , so $p=\dfrac{nh}{2\pi r}$ .

(A)

Topics:Bohr model and hydrogen spectrum

JEE Main 2022 · 25 Jul · Shift 1, Physics question 48