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← JEE Main 2022 · 25 Jul · Shift 1
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JEE Main 2022 · 25 Jul · Shift 1, Physics question 46

Time taken by light to travel in two different materials A and B of refractive indices μA\mu_A and μB\mu_B of same thickness is t1t_1 and t2t_2 respectively. If t2−t1=5×10−10t_2-t_1=5\times10^{-10} s and the ratio of μA\mu_A to μB\mu_B is 1 : 2. Then, the thickness of material, in meter is : (Given vAv_A and vBv_B are velocities of light in A and B materials respectively.)

Choose one option
Answer and worked solution

Official answer: A

Times. t=μdct=\frac{\mu d}c, so t2−t1=(μB−μA)dc=μAdc=dvAt_2-t_1=\frac{(\mu_B-\mu_A)d}c=\frac{\mu_Ad}c=\frac d{v_A}.

Thickness d=5×10−10vAd=5\times10^{-10}v_A m.

(A)