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← JEE Main 2022 · 25 Jul · Shift 1
PhysicsSingle correct+4 / -1Question 36 of 90

JEE Main 2022 · 25 Jul · Shift 1, Physics question 36

Three identical particles A, B and C of mass 100 kg each are placed in a straight line with AB = BC = 13 m. The gravitational force on a fourth particle P of the same mass is F, when placed at a distance 13 m from the particle B on the perpendicular bisector of the line AC. The value of F will be approximately :

Choose one option
Answer and worked solution

Official answer: B

Forces on P. From B: G⋅104169≈59G\dfrac{G\cdot10^4}{169}\approx59G. From A and C (distance 13213\sqrt2), along PB: 2⋅G⋅104338⋅12≈42G2\cdot\dfrac{G\cdot10^4}{338}\cdot\frac1{\sqrt2}\approx42G. Total about 100G100G.

(B)