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JEE Main 2022 · 25 Jul · Shift 1, Physics question 34

A body of mass 0.5 kg travels on straight line path with velocity v=(3x2+4)v=\left(3x^2+4\right) m/s. The net workdone by the force during its displacement from x=0x=0 to x=2x=2 m is :

Choose one option
Answer and worked solution

Official answer: B

Work-energy. vv goes from 4 to 16 m s−1^{-1}: W=12(0.5)(256−16)=60W=\frac12(0.5)(256-16)=60 J.

(B)

Topics:Work-energy theorem
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