JEE Main 2022 · 25 Jul · Shift 1 · Mathematics Q19

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MathematicsSingle correct+4 / -1Question 19 of 90

A tower PQ stands on a horizontal ground with base Q on the ground. The point R divides the tower in two parts such that QR = 15 m. If from a point A on the ground the angle of elevation of R is 60° and the part PR of the tower subtends an angle of 15° at A, then the height of the tower is :

5\left(2\sqrt3+3\right)

5\left(\sqrt3+3\right)

10\left(\sqrt3+1\right)

10\left(2\sqrt3+1\right)

Answer and worked solution

Official answer: A

Distance $AQ=\frac{15}{\sqrt3}=5\sqrt3$ . The top P is seen at $75°$ : $PQ=5\sqrt3\tan75°=5\sqrt3(2+\sqrt3)=5(2\sqrt3+3)$ .

(A)

Topics:Heights and distances

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JEE Main 2022 · 25 Jul · Shift 1, Mathematics question 19